WebMar 8, 2024 · You will need to use the derivative of y = ln x and the chain rule. So you will get y' = 4·1/ (x 3 – 1)· (3x 2) + (1/2)·1/ (3x – 1)· (3) –1/ (x 2 + 4)· (2x). From here, you will simplify each term to finish finding the derivative. y' = 12x 2 / (x 3 – 1) +3/ [2 (3x – 1)] – 2x/ (x 2 + 4) Upvote • 0 Downvote. Add comment. Report. WebPlease show all Chegg.com. Math. Calculus. Calculus questions and answers. Find the derivative of the function. Please show all work.y=x^6lnx-1/3x^3. Question: Find the derivative of the function. Please show all work.y=x^6lnx-1/3x^3.
Implicit differentiation review (article) Khan Academy
WebNov 2, 2015 · Explanation: Method 1 y = (3x + 1)2 Assume the function in the bracket as some other variable say t. t = 3x +1 dt dx = 3 y = t2 dy dx = dy dt ⋅ dt dx = 2t ⋅ 3 dy dx = 6(3x + 1) Method 2 If you can expand everything and find the derivative y = (3x + 1)2 y = 9x2 +6x + 1 dy dx = 18x +6 dy dx = 6(3x + 1) Answer link WebApr 12, 2015 · How do you find the derivative of quotient 1 − 3x 1 + 3x? Calculus Basic Differentiation Rules Quotient Rule 2 Answers Alan P. Apr 12, 2015 The Quotient Rule for Derivatives says d g(x) h(x) dx = g'(x) ⋅ h(x) −g(x) ⋅ h'(x) h2(x) So d( 1−3x 1+3x) dx = ( −3)(1 +3x) − (1 − 3x)(3) (1 + 3x)2 = −6 9x2 +6x +1 Answer link Anees Apr 12, 2015 −6 (1 + 3x)2 how brush cat teeth
Derivative Calculator - Symbolab
WebOct 23, 2024 · The derivative of 1/x 3 can be expressed mathematically as d/dx(1/x 3) or (1/x 3)$’$. The derivative formula of 1 divided by x cube is given below: d/dx(1/x 3) = -3/x … WebA short cut for implicit differentiation is using the partial derivative (∂/∂x). When you use the partial derivative, you treat all the variables, except the one you are differentiating with respect to, like a constant. For example ∂/∂x [2xy + y^2] = 2y. In this case, y is treated as a … WebDerivative Calculator Step 1: Enter the function you want to find the derivative of in the editor. The Derivative Calculator supports solving first, second...., fourth derivatives, as … how brutal were the mayans